Plane¶
Geometrical Planes.
Contains¶
Plane
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class
sympy.geometry.plane.
Plane
[source]¶ A plane is a flat, two-dimensional surface. A plane is the two-dimensional analogue of a point (zero-dimensions), a line (one-dimension) and a solid (three-dimensions). A plane can generally be constructed by two types of inputs. They are three non-collinear points and a point and the plane’s normal vector.
Examples
>>> from sympy import Plane, Point3D >>> from sympy.abc import x >>> Plane(Point3D(1, 1, 1), Point3D(2, 3, 4), Point3D(2, 2, 2)) Plane(Point3D(1, 1, 1), (-1, 2, -1)) >>> Plane((1, 1, 1), (2, 3, 4), (2, 2, 2)) Plane(Point3D(1, 1, 1), (-1, 2, -1)) >>> Plane(Point3D(1, 1, 1), normal_vector=(1,4,7)) Plane(Point3D(1, 1, 1), (1, 4, 7))
Attributes
p1 normal_vector -
angle_between
(o)[source]¶ Angle between the plane and other geometric entity.
Parameters: LinearEntity3D, Plane. Returns: angle : angle in radians Notes
This method accepts only 3D entities as it’s parameter, but if you want to calculate the angle between a 2D entity and a plane you should first convert to a 3D entity by projecting onto a desired plane and then proceed to calculate the angle.
Examples
>>> from sympy import Point3D, Line3D, Plane >>> a = Plane(Point3D(1, 2, 2), normal_vector=(1, 2, 3)) >>> b = Line3D(Point3D(1, 3, 4), Point3D(2, 2, 2)) >>> a.angle_between(b) -asin(sqrt(21)/6)
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arbitrary_point
(t=None)[source]¶ Returns an arbitrary point on the Plane; varying \(t\) from 0 to 2*pi will move the point in a circle of radius 1 about p1 of the Plane.
Returns: Point3D Examples
>>> from sympy.geometry.plane import Plane >>> from sympy.abc import t >>> p = Plane((0, 0, 0), (0, 0, 1), (0, 1, 0)) >>> p.arbitrary_point(t) Point3D(0, cos(t), sin(t)) >>> _.distance(p.p1).simplify() 1
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static
are_concurrent
(*planes)[source]¶ Is a sequence of Planes concurrent?
Two or more Planes are concurrent if their intersections are a common line.
Parameters: planes: list Returns: Boolean Examples
>>> from sympy import Plane, Point3D >>> a = Plane(Point3D(5, 0, 0), normal_vector=(1, -1, 1)) >>> b = Plane(Point3D(0, -2, 0), normal_vector=(3, 1, 1)) >>> c = Plane(Point3D(0, -1, 0), normal_vector=(5, -1, 9)) >>> Plane.are_concurrent(a, b) True >>> Plane.are_concurrent(a, b, c) False
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distance
(o)[source]¶ Distance beteen the plane and another geometric entity.
Parameters: Point3D, LinearEntity3D, Plane. Returns: distance Notes
This method accepts only 3D entities as it’s parameter, but if you want to calculate the distance between a 2D entity and a plane you should first convert to a 3D entity by projecting onto a desired plane and then proceed to calculate the distance.
Examples
>>> from sympy import Point, Point3D, Line, Line3D, Plane >>> a = Plane(Point3D(1, 1, 1), normal_vector=(1, 1, 1)) >>> b = Point3D(1, 2, 3) >>> a.distance(b) sqrt(3) >>> c = Line3D(Point3D(2, 3, 1), Point3D(1, 2, 2)) >>> a.distance(c) 0
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equation
(x=None, y=None, z=None)[source]¶ The equation of the Plane.
Examples
>>> from sympy import Point3D, Plane >>> a = Plane(Point3D(1, 1, 2), Point3D(2, 4, 7), Point3D(3, 5, 1)) >>> a.equation() -23*x + 11*y - 2*z + 16 >>> a = Plane(Point3D(1, 4, 2), normal_vector=(6, 6, 6)) >>> a.equation() 6*x + 6*y + 6*z - 42
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intersection
(o)[source]¶ The intersection with other geometrical entity.
Parameters: Point, Point3D, LinearEntity, LinearEntity3D, Plane Returns: List Examples
>>> from sympy import Point, Point3D, Line, Line3D, Plane >>> a = Plane(Point3D(1, 2, 3), normal_vector=(1, 1, 1)) >>> b = Point3D(1, 2, 3) >>> a.intersection(b) [Point3D(1, 2, 3)] >>> c = Line3D(Point3D(1, 4, 7), Point3D(2, 2, 2)) >>> a.intersection(c) [Point3D(2, 2, 2)] >>> d = Plane(Point3D(6, 0, 0), normal_vector=(2, -5, 3)) >>> e = Plane(Point3D(2, 0, 0), normal_vector=(3, 4, -3)) >>> d.intersection(e) [Line3D(Point3D(78/23, -24/23, 0), Point3D(147/23, 321/23, 23))]
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is_coplanar
(o)[source]¶ Returns True if \(o\) is coplanar with self, else False.
Examples
>>> from sympy import Plane, Point3D >>> o = (0, 0, 0) >>> p = Plane(o, (1, 1, 1)) >>> p2 = Plane(o, (2, 2, 2)) >>> p == p2 False >>> p.is_coplanar(p2) True
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is_parallel
(l)[source]¶ Is the given geometric entity parallel to the plane?
Parameters: LinearEntity3D or Plane Returns: Boolean Examples
>>> from sympy import Plane, Point3D >>> a = Plane(Point3D(1,4,6), normal_vector=(2, 4, 6)) >>> b = Plane(Point3D(3,1,3), normal_vector=(4, 8, 12)) >>> a.is_parallel(b) True
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is_perpendicular
(l)[source]¶ is the given geometric entity perpendicualar to the given plane?
Parameters: LinearEntity3D or Plane Returns: Boolean Examples
>>> from sympy import Plane, Point3D >>> a = Plane(Point3D(1,4,6), normal_vector=(2, 4, 6)) >>> b = Plane(Point3D(2, 2, 2), normal_vector=(-1, 2, -1)) >>> a.is_perpendicular(b) True
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normal_vector
¶ Normal vector of the given plane.
Examples
>>> from sympy import Point3D, Plane >>> a = Plane(Point3D(1, 1, 1), Point3D(2, 3, 4), Point3D(2, 2, 2)) >>> a.normal_vector (-1, 2, -1) >>> a = Plane(Point3D(1, 1, 1), normal_vector=(1, 4, 7)) >>> a.normal_vector (1, 4, 7)
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p1
¶ The only defining point of the plane. Others can be obtained from the arbitrary_point method.
See also
Examples
>>> from sympy import Point3D, Plane >>> a = Plane(Point3D(1, 1, 1), Point3D(2, 3, 4), Point3D(2, 2, 2)) >>> a.p1 Point3D(1, 1, 1)
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parallel_plane
(pt)[source]¶ Plane parallel to the given plane and passing through the point pt.
Parameters: pt: Point3D Returns: Plane Examples
>>> from sympy import Plane, Point3D >>> a = Plane(Point3D(1, 4, 6), normal_vector=(2, 4, 6)) >>> a.parallel_plane(Point3D(2, 3, 5)) Plane(Point3D(2, 3, 5), (2, 4, 6))
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perpendicular_line
(pt)[source]¶ A line perpendicular to the given plane.
Parameters: pt: Point3D Returns: Line3D Examples
>>> from sympy import Plane, Point3D, Line3D >>> a = Plane(Point3D(1,4,6), normal_vector=(2, 4, 6)) >>> a.perpendicular_line(Point3D(9, 8, 7)) Line3D(Point3D(9, 8, 7), Point3D(11, 12, 13))
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perpendicular_plane
(*pts)[source]¶ Return a perpendicular passing through the given points. If the direction ratio between the points is the same as the Plane’s normal vector then, to select from the infinite number of possible planes, a third point will be chosen on the z-axis (or the y-axis if the normal vector is already parallel to the z-axis). If less than two points are given they will be supplied as follows: if no point is given then pt1 will be self.p1; if a second point is not given it will be a point through pt1 on a line parallel to the z-axis (if the normal is not already the z-axis, otherwise on the line parallel to the y-axis).
Parameters: pts: 0, 1 or 2 Point3D Returns: Plane Examples
>>> from sympy import Plane, Point3D, Line3D >>> a, b = Point3D(0, 0, 0), Point3D(0, 1, 0) >>> Z = (0, 0, 1) >>> p = Plane(a, normal_vector=Z) >>> p.perpendicular_plane(a, b) Plane(Point3D(0, 0, 0), (1, 0, 0))
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projection
(pt)[source]¶ Project the given point onto the plane along the plane normal.
Parameters: Point or Point3D Returns: Point3D Examples
>>> from sympy import Plane, Point, Point3D >>> A = Plane(Point3D(1, 1, 2), normal_vector=(1, 1, 1))
The projection is along the normal vector direction, not the z axis, so (1, 1) does not project to (1, 1, 2) on the plane A:
>>> b = Point(1, 1) >>> A.projection(b) Point3D(5/3, 5/3, 2/3) >>> _ in A True
But the point (1, 1, 2) projects to (1, 1) on the XY-plane:
>>> XY = Plane((0, 0, 0), (0, 0, 1)) >>> XY.projection((1, 1, 2)) Point3D(1, 1, 0)
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projection_line
(line)[source]¶ Project the given line onto the plane through the normal plane containing the line.
Parameters: LinearEntity or LinearEntity3D Returns: Point3D, Line3D, Ray3D or Segment3D Notes
For the interaction between 2D and 3D lines(segments, rays), you should convert the line to 3D by using this method. For example for finding the intersection between a 2D and a 3D line, convert the 2D line to a 3D line by projecting it on a required plane and then proceed to find the intersection between those lines.
Examples
>>> from sympy import Plane, Line, Line3D, Point, Point3D >>> a = Plane(Point3D(1, 1, 1), normal_vector=(1, 1, 1)) >>> b = Line(Point(1, 1), Point(2, 2)) >>> a.projection_line(b) Line3D(Point3D(4/3, 4/3, 1/3), Point3D(5/3, 5/3, -1/3)) >>> c = Line3D(Point3D(1, 1, 1), Point3D(2, 2, 2)) >>> a.projection_line(c) Point3D(1, 1, 1)
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