DOKK / manpages / debian 11 / libnumber-tolerant-perl / Number::Tolerant::Union.3pm.en
Number::Tolerant::Union(3pm) User Contributed Perl Documentation Number::Tolerant::Union(3pm)

Number::Tolerant::Union - unions of tolerance ranges

version 1.708

 use Number::Tolerant;
 my $range1 = tolerance(10 => to => 12);
 my $range2 = tolerance(14 => to => 16);
 my $union = $range1 | $range2;
 if ($11 == $union) { ... } # this will happen
 if ($12 == $union) { ... } # so will this
 if ($13 == $union) { ... } # nothing will happen here
 if ($14 == $union) { ... } # this will happen
 if ($15 == $union) { ... } # so will this

Number::Tolerant::Union is used by Number::Tolerant to represent the union of multiple tolerances. A subset of the same operators that function on a tolerance will function on a union of tolerances, as listed below.

  my $union = Number::Tolerant::Union->new(@list_of_tolerances);

There is a "new" method on the Number::Tolerant::Union class, but unions are meant to be created with the "|" operator on a Number::Tolerant tolerance.

The arguments to "new" are a list of numbers or tolerances to be unioned.

Intersecting ranges are not converted into a single range, but this may change in the future. (For example, the union of "5 to 10" and "7 to 12" is not "5 to 12.")

This method will return a list of all the acceptable options for the union.

Tolerance unions overload a few operations, mostly comparisons.

Unions numify to undef. If there's a better idea, I'd love to hear it.
A tolerance stringifies to a short description of itself. This is a set of the union's options, parentheses-enclosed and joined by the word "or"
A number is equal to a union if it is equal to any of its options.
A number is greater than a union if it is greater than all its options.

A number is less than a union if it is less than all its options.

An intersection ("&") with a union is commutted across all options. In other words:

 (a | b | c) & d  ==yields==> ((a & d) | (b & d) | (c & d))
    

Options that have no intersection with the new element are dropped. The intersection of a constant number and a union yields that number, if the number was in the union's ranges and otherwise yields nothing.

Who knows. Collapsing overlapping options, probably.

Ricardo Signes <rjbs@cpan.org>

This software is copyright (c) 2004 by Ricardo Signes.

This is free software; you can redistribute it and/or modify it under the same terms as the Perl 5 programming language system itself.

2016-02-22 perl v5.22.1