VistaIOExtractAttr(3) | Library Functions Manual | VistaIOExtractAttr(3) |
VistaIOExtractAttr - fetch and delete an attribute
VistaIOBoolean VistaIOExtractAttr (list, name, dict, repn, value, required)
VistaIOAttrList list; VistaIOStringConst name; VistaIODictEntry *dict; VistaIORepnKind repn; VistaIOPointer value; VistaIOBoolean required;
VistaIOExtractAttr locates the first attribute named name in list, removing it if found and returning its value.
If a dictionary, dict, has been provided and the attribute's value is stored as a character string, the routine determines whether the string is a keyword defined in the dictionary. If so, it uses the value associated with that keyword rather than the attribute's original value. (See the VistaIOdictionary(3) manual page.)
The value obtained directly from the attribute, or indirectly via the dictionary, is converted to the representation repn and then stored at the location pointed to by value. The repn argument may have any VistaIORepnKind value or any of the values returned by VistaIORegisterType(3). However, an attribute value that is a string can only be returned as a string or a number, and other attribute values can only be returned in the representation with which they are stored. (The VistaIOGetAttrRepn(3) macro can be used to determine an attribute value's representation.)
VistaIOExtractAttr returns FALSE if required is TRUE and no attribute named name is found. If also returns FALSE if an attribute is found but its value cannot be converted to the desired representation. Otherwise, VistaIOExtractAttr returns TRUE while perhaps modifying the list list and storing a value at value.
VistaIOGetAttr(3), VistaIOGetAttrValue(3),
VistaIOLookupAttr(3), VistaIODeleteAttr(3),
VistaIOInsertAttr(3),
VistaIOattribute(3), VistaIOdictionary(3),
VistaIOExtractAttr is meant for use with attribute lists representing sets, in which each attribute name occurs at most once. If list contains multiple attributes named name, only the first is located.
The value argument must point to sufficient storage to contain a value of the representation requested. Neither the routine nor the C compiler can automatically check that this is so.
If a string value is returned, it will be in newly-allocated storage. Release the storage with VistaIOFree(3) when done with the string.
Art Pope <pope@cs.ubc.ca>
Adaption to vistaio: Gert Wollny <gw.fossdev@gmail.com>
24 April 1993 | VistaIO Version 1.2.14 |